13x^2-4x-9=0

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Solution for 13x^2-4x-9=0 equation:



13x^2-4x-9=0
a = 13; b = -4; c = -9;
Δ = b2-4ac
Δ = -42-4·13·(-9)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-22}{2*13}=\frac{-18}{26} =-9/13 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+22}{2*13}=\frac{26}{26} =1 $

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